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51 lines
900 B
Markdown
51 lines
900 B
Markdown
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# 6-1 计算两个复数之积
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本题要求实现一个计算复数之积的简单函数。
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### 函数接口定义:
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```c++
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struct complex multiply(struct complex x, struct complex y);
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```
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其中`struct complex`是复数结构体,其定义如下:
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```c++
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struct complex{
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int real;
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int imag;
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};
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```
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### 裁判测试程序样例:
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```c++
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#include <stdio.h>
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struct complex{
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int real;
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int imag;
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};
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struct complex multiply(struct complex x, struct complex y);
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int main()
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{
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struct complex product, x, y;
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scanf("%d%d%d%d", &x.real, &x.imag, &y.real, &y.imag);
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product = multiply(x, y);
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printf("(%d+%di) * (%d+%di) = %d + %di\n",
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x.real, x.imag, y.real, y.imag, product.real, product.imag);
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return 0;
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}
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/* 你的代码将被嵌在这里 */
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```
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### 输入样例:
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```in
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3 4 5 6
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```
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### 输出样例:
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```out
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(3+4i) * (5+6i) = -9 + 38i
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```
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