# 6-1 计算两个复数之积 本题要求实现一个计算复数之积的简单函数。 ### 函数接口定义: ```c++ struct complex multiply(struct complex x, struct complex y); ``` 其中`struct complex`是复数结构体,其定义如下: ```c++ struct complex{ int real; int imag; }; ``` ### 裁判测试程序样例: ```c++ #include struct complex{ int real; int imag; }; struct complex multiply(struct complex x, struct complex y); int main() { struct complex product, x, y; scanf("%d%d%d%d", &x.real, &x.imag, &y.real, &y.imag); product = multiply(x, y); printf("(%d+%di) * (%d+%di) = %d + %di\n", x.real, x.imag, y.real, y.imag, product.real, product.imag); return 0; } /* 你的代码将被嵌在这里 */ ``` ### 输入样例: ```in 3 4 5 6 ``` ### 输出样例: ```out (3+4i) * (5+6i) = -9 + 38i ```