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OI-codes/BZOJ/3378/3378.cpp

33 lines
554 B
C++

#include <iostream>
using std::cin;
using std::cout;
const char endl = '\n';
const int N = 5e4 + 5;
int n;
long long ans;
std::pair<int, int> p[N];
int main() {
std::ios::sync_with_stdio(false);
cin.tie(nullptr);
cin >> n;
for (int i = 1; i <= n; i++) {
cin >> p[i].first >> p[i].second;
}
for (int i = 1; i <= n; i++) {
for (int j = 1; j < i; j++) {
ans += 1ll * std::max(p[i].first, p[j].first) * std::abs(p[i].second - p[j].second);
}
}
cout << ans << endl;
return 0;
}