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OI-codes/BZOJ/2794/2794.cpp

65 lines
1.5 KiB
C++

#include <iostream>
#include <algorithm>
#include <limits>
#include <tuple>
using std::cin;
using std::cout;
const char endl = '\n';
const int N = 1005,
P = 1e6 + 5;
int n, p, f[P];
bool ans[P];
std::tuple<int, int, int> a[N];
std::tuple<int, int, int, int> b[P];
int main() {
std::ios::sync_with_stdio(false);
cin.tie(nullptr);
cin >> n;
for (int i = 1; i <= n; i++) {
cin >> std::get<2>(a[i]) >> std::get<0>(a[i]) >> std::get<1>(a[i]);
}
std::sort(a + 1, a + 1 + n, [&](auto a, auto b) {
return std::get<0>(a) < std::get<0>(b);
});
cin >> p;
for (int i = 1; i <= p; i++) {
cin >> std::get<1>(b[i]) >> std::get<2>(b[i]) >> std::get<3>(b[i]);
std::get<0>(b[i]) = i;
}
std::sort(b + 1, b + 1 + p, [&](auto a, auto b) {
return std::get<1>(a) < std::get<1>(b);
});
f[0] = std::numeric_limits<int>::max();
for (int i = 1, j = 1; i <= p; i++) {
while (std::get<0>(a[j]) <= std::get<1>(b[i]) && j <= n) {
for (int k = 100000; k >= std::get<2>(a[j]); k--) {
f[k] = std::max(f[k],
std::min(f[k - std::get<2>(a[j])],
std::get<1>(a[j])));
}
j++;
}
if (f[std::get<2>(b[i])] > std::get<1>(b[i]) + std::get<3>(b[i])) {
ans[std::get<0>(b[i])] = true;
}
}
for (int i = 1; i <= p; i++) {
cout << (ans[i] ? "TAK" : "NIE") << endl;
}
return 0;
}