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OI-codes/S2OJ/1139/1139.cpp

150 lines
3.2 KiB
C++

#include <iostream>
#include <algorithm>
#include <cstring>
#include <iterator>
#include <limits>
#include <memory>
#include <queue>
#include <string>
#include <unordered_map>
#include <vector>
using std::cin;
using std::cout;
const char endl = '\n';
int k, nxt[15][1005];
long long sum[15][1005], f[2][1005][(1 << 14) + 5],
ans = std::numeric_limits<long long>::min();
std::string s;
std::vector<std::string> a{""};
int root, cnt;
struct node {
int val;
int child[26], fail;
node()
: val(0), fail(0) {
std::fill(std::begin(child), std::end(child), 0);
}
} tr[1005];
void insert(std::string s, const int& _val) {
int cur = root;
for (char c : s) {
if (!tr[cur].child[c - 'a']) {
tr[cur].child[c - 'a'] = ++cnt;
}
cur = tr[cur].child[c - 'a'];
}
tr[cur].val += _val;
}
void build() {
std::queue<int> q;
for (int i = 0; i < 26; i++) {
if (tr[root].child[i]) {
q.emplace(tr[root].child[i]);
}
}
while (!q.empty()) {
int cur = q.front();
q.pop();
for (int i = 0; i < 26; i++) {
if (tr[cur].child[i]) {
tr[tr[cur].child[i]].fail = tr[tr[cur].fail].child[i];
q.emplace(tr[cur].child[i]);
tr[tr[cur].child[i]].val += tr[tr[tr[cur].child[i]].fail].val;
} else {
tr[cur].child[i] = tr[tr[cur].fail].child[i];
}
}
}
}
int main() {
std::ios::sync_with_stdio(false);
cin.tie(nullptr);
cin >> k;
for (int i = 1; i <= k; i++) {
std::string t;
int c;
cin >> t >> c;
insert(t, c);
}
cin >> s;
build();
for (char c : s) {
if (c == '?') {
a.emplace_back("");
} else {
a.back().push_back(c);
}
}
for (int i = 0; i < a.size(); i++) {
for (int j = 0; j <= cnt; j++) {
int cur = j;
for (char c : a[i]) {
cur = tr[cur].child[c - 'a'];
sum[i][j] += tr[cur].val;
}
nxt[i][j] = cur;
}
}
memset(f, 0xc0, sizeof(f));
f[0][0][0] = 0;
for (int i = 0, x = 0; i < a.size(); i++, x ^= 1) {
memset(f[x ^ 1], 0xc0, sizeof(f[x ^ 1]));
for (int j = 0; j <= cnt; j++) {
for (int s = 0; s < 1 << 14; s++) {
if (f[x][j][s] < -0x3f3f3f3f3f3f3f3f) continue;
int p = nxt[i][j];
if (i + 1 < a.size()) {
for (int k = 0; k < 14; k++) {
if (s & (1 << k)) continue;
f[x ^ 1][tr[p].child[k]][s | (1 << k)] = std::max(
f[x ^ 1][tr[p].child[k]][s | (1 << k)],
f[x][j][s] + sum[i][j] + tr[tr[p].child[k]].val);
}
} else {
f[x ^ 1][p][s] = std::max(f[x ^ 1][p][s], f[x][j][s] + sum[i][j]);
}
}
}
}
for (int i = 0; i <= cnt; i++) {
for (int s = 0; s < 1 << 14; s++) {
ans = std::max(ans, f[a.size() & 1][i][s]);
}
}
cout << ans << endl;
return 0;
}