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OI-codes/BZOJ/4380/4380.cpp

112 lines
2.9 KiB
C++

#include <iostream>
#include <algorithm>
#include <numeric>
#include <tuple>
#include <vector>
using std::cin;
using std::cout;
const char endl = '\n';
int main() {
std::ios::sync_with_stdio(false);
cin.tie(nullptr);
int n, m;
cin >> n >> m;
std::vector<std::tuple<int, int, int>> data(m);
std::vector<int> nums;
for (auto& e : data) {
int a, b, c;
cin >> a >> b >> c;
e = std::make_tuple(a - 1, b - 1, c);
nums.push_back(c);
}
std::sort(nums.begin(), nums.end());
nums.erase(std::unique(nums.begin(), nums.end()), nums.end());
for (auto& e : data) {
std::get<2>(e) = std::lower_bound(nums.begin(), nums.end(), std::get<2>(e)) - nums.begin();
}
std::vector<std::vector<int>> g(n, std::vector<int>(nums.size(), 0));
std::vector<std::vector<std::vector<int>>>
f(n, std::vector<std::vector<int>>(n, std::vector<int>(nums.size(), 0))),
pos(n, std::vector<std::vector<int>>(n, std::vector<int>(nums.size(), 0))),
pre(n, std::vector<std::vector<int>>(n, std::vector<int>(nums.size(), 0)));
for (int len = 1; len <= n; len++) {
for (int l = 0, r = l + len - 1; r < n; l++, r++) {
std::for_each(g.begin() + l, g.begin() + r + 1, [&](auto& v) {
std::fill(v.begin(), v.end(), 0);
});
for (const auto& e : data) {
int a, b, c;
std::tie(a, b, c) = e;
if (l <= a && b <= r) {
std::for_each(g.begin() + a, g.begin() + b + 1, [&](auto& v) { v[c]++; });
}
}
std::for_each(g.begin() + l, g.begin() + r + 1, [&](auto& v) {
std::partial_sum(v.rbegin(), v.rend(), v.rbegin());
});
for (int i = nums.size() - 1; i >= 0; i--) {
int max = 0;
for (int j = l; j <= r; j++) {
int t = (j > 0 ? f[l][j - 1][i] : 0)
+ (j + 1 < n ? f[j + 1][r][i] : 0)
+ g[j][i] * nums[i];
if (max <= t) {
max = t;
pos[l][r][i] = j;
}
}
if (i + 1 == nums.size() || f[l][r][i + 1] <= max) {
f[l][r][i] = max;
pre[l][r][i] = i;
} else {
f[l][r][i] = f[l][r][i + 1];
pre[l][r][i] = pre[l][r][i + 1];
}
}
}
}
cout << f[0][n - 1][0] << endl;
std::vector<int> ans(n);
auto dfs = [&](int l, int r, int k, auto&& dfs) -> void {
if (l > r) return;
int p = pos[l][r][k = pre[l][r][k]];
ans[p] = nums[k];
dfs(l, p - 1, k, dfs);
dfs(p + 1, r, k, dfs);
};
dfs(0, n - 1, 0, dfs);
for (const int& x : ans) {
cout << x << ' ';
}
cout << endl;
return 0;
}