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OI-codes/S2OJ/1822/1822.cpp
2023-01-17 21:33:08 +08:00

151 lines
2.5 KiB
C++

#include <iostream>
#include <algorithm>
#include <numeric>
#include <vector>
using std::cin;
using std::cout;
const char endl = '\n';
const int N = 1e5 + 5;
int n, a[N], c[N], siz[N], max[N],
_cnt[N << 1], *cnt(_cnt + N), pos[N], sum[N], root, ans;
std::vector<int> g[N];
bool vis[N];
void get_root(int u, int f, int s) {
siz[u] = 1;
max[u] = 0;
for (auto v : g[u]) {
if (v == f || vis[v]) continue;
get_root(v, u, s);
siz[u] += siz[v];
max[u] = std::max(max[u], siz[v]);
}
max[u] = std::max(max[u], s - siz[u]);
if (!root || max[u] < max[root]) {
root = u;
}
}
void add(int u, int f, int d) {
cnt[d]++;
for (int v : g[u]) {
if (v == f || vis[v]) continue;
add(v, u, d + c[v]);
}
}
void del(int u, int f, int d) {
cnt[d]--;
for (int v : g[u]) {
if (v == f || vis[v]) continue;
del(v, u, d + c[v]);
}
}
void calc(int u, int f, int d) {
sum[pos[u]] += cnt[-d];
for (int v : g[u]) {
if (v == f || vis[v]) continue;
calc(v, u, d + c[v]);
}
}
void solve(int u) {
vis[u] = true;
cnt[0]++;
for (int v : g[u]) {
if (vis[v]) continue;
calc(v, u, c[u] + c[v]);
add(v, u, c[v]);
}
sum[pos[u]] += cnt[-c[u]];
cnt[0]--;
for (int v : g[u]) {
if (vis[v]) continue;
del(v, u, c[v]);
}
std::for_each(g[u].rbegin(), g[u].rend(), [&](int v) -> void {
if (vis[v]) return;
calc(v, u, c[u] + c[v]);
add(v, u, c[v]);
});
for (int v : g[u]) {
if (vis[v]) continue;
del(v, u, c[v]);
}
for (int v : g[u]) {
if (vis[v]) continue;
root = 0;
get_root(v, 0, siz[v]);
get_root(root, 0, siz[v]);
solve(root);
}
}
int main() {
std::ios::sync_with_stdio(false);
cin.tie(nullptr);
cin >> n;
for (int i = 1, x; i <= n; i++) {
cin >> x;
c[i] = x ? 1 : -1;
}
for (int i = 1, x, y; i < n; i++) {
cin >> x >> y;
g[x].emplace_back(y);
g[y].emplace_back(x);
}
for (int i = 1; i <= n; i++) {
cin >> a[i];
pos[a[i]] = i;
}
get_root(1, 0, n);
get_root(root, 0, n);
solve(root);
std::partial_sum(sum + 1, sum + 1 + n, sum + 1);
for (int l = 1, r = 1; l <= n; l++) {
while (r <= n && sum[r] - sum[l - 1] <= sum[n] - sum[r] + sum[l - 1]) r++;
ans += n - r + 1;
}
cout << ans << endl;
return 0;
}