mirror of
https://git.sb/baoshuo/OI-codes.git
synced 2024-12-25 09:31:59 +00:00
135 lines
2.6 KiB
C++
135 lines
2.6 KiB
C++
#include <iostream>
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#include <algorithm>
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#include <limits>
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#include <queue>
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#include <tuple>
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#include <vector>
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using std::cin;
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using std::cout;
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const char endl = '\n';
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const int N = 1e6 + 5;
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int n, s, t, f[N], ans;
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std::tuple<int, int, int> points[N];
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int idx, head[N << 1], ver[N << 2], edge[N << 2], next[N << 2];
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int cur[N << 1], dist[N << 1];
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void add(int u, int v, int w) {
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next[idx] = head[u];
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ver[idx] = v;
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edge[idx] = w;
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head[u] = idx++;
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}
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bool bfs() {
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std::fill_n(dist, N << 1, 0);
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std::queue<int> q;
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q.push(s);
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dist[s] = 1;
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cur[s] = head[s];
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while (!q.empty()) {
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int u = q.front();
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q.pop();
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for (int i = head[u]; ~i; i = next[i]) {
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int v = ver[i],
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w = edge[i];
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if (w && !dist[v]) {
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dist[v] = dist[u] + 1;
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cur[v] = head[v];
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if (v == t) return true;
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q.push(v);
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}
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}
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}
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return false;
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}
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int dinic(int u, int limit) {
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if (u == t) return limit;
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int flow = 0;
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for (int i = cur[u]; ~i && flow < limit; i = next[i]) {
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cur[u] = i;
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int v = ver[i],
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w = edge[i];
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if (dist[v] == dist[u] + 1 && w) {
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int k = dinic(v, std::min(w, limit - flow));
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if (!k) {
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dist[v] = 0;
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} else {
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flow += k;
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edge[i] -= k;
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edge[i ^ 1] += k;
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}
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}
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}
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return flow;
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}
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int main() {
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std::ios::sync_with_stdio(false);
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cin.tie(nullptr);
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std::fill_n(head, N << 1, -1);
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cin >> n;
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for (int i = 1; i <= n; i++) {
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cin >> std::get<0>(points[i]) >> std::get<1>(points[i]) >> std::get<2>(points[i]);
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}
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std::sort(points + 1, points + 1 + n);
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for (int i = 1; i <= n; i++) {
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f[i] = 1;
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for (int j = 1; j < i; j++) {
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int x1, y1, z1,
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x2, y2, z2;
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std::tie(x1, y1, z1) = points[i];
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std::tie(x2, y2, z2) = points[j];
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if (x2 < x1 && y2 < y1 && z2 < z1) {
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f[i] = std::max(f[i], f[j] + 1);
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add(j, i + n, 1);
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add(i + n, j, 0);
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}
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}
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ans = std::max(ans, f[i]);
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}
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s = n * 2 + 1, t = s + 1;
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for (int i = 1; i <= n; i++) {
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add(s, i, 1);
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add(i, s, 0);
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add(i + n, t, 1);
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add(t, i + n, 0);
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}
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int res = 0, flow;
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while (bfs()) {
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while (flow = dinic(s, std::numeric_limits<int>::max())) res += flow;
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}
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cout << ans << endl
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<< n - res << endl;
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return 0;
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}
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