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OI-codes/BZOJ/1257/1257.cpp
2022-03-25 08:48:50 +08:00

20 lines
358 B
C++

#include <cmath>
#include <iostream>
using std::cin;
using std::cout;
using std::endl;
long long n, k, ans;
int main() {
cin >> n >> k;
ans = n * k;
for (int x = 1, gx; x <= n; x = gx + 1) {
gx = k / x ? std::min(k / (k / x), n) : n;
ans -= (k / x) * (x + gx) * (gx - x + 1) / 2;
}
cout << ans << endl;
return 0;
}