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20 lines
358 B
C++
20 lines
358 B
C++
#include <cmath>
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#include <iostream>
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using std::cin;
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using std::cout;
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using std::endl;
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long long n, k, ans;
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int main() {
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cin >> n >> k;
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ans = n * k;
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for (int x = 1, gx; x <= n; x = gx + 1) {
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gx = k / x ? std::min(k / (k / x), n) : n;
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ans -= (k / x) * (x + gx) * (gx - x + 1) / 2;
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}
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cout << ans << endl;
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return 0;
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}
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