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OI-codes/Luogu/P2254/P2254.cpp

109 lines
3.7 KiB
C++

#include <iostream>
#include <deque>
using std::cin;
using std::cout;
const char endl = '\n';
const int N = 205;
int n, m, x, y, k, s, t, d, f[N][N], ans;
bool g[N][N];
int main() {
std::ios::sync_with_stdio(false);
cin.tie(nullptr);
cin >> n >> m >> x >> y >> k;
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= m; j++) {
char c;
cin >> c;
g[i][j] = c == 'x';
f[i][j] = -0x3f3f3f3f;
}
}
f[x][y] = 0;
for (int i = 1; i <= k; i++) {
cin >> s >> t >> d;
int len = t - s + 1;
switch (d) {
case 1: { // 上
for (int y = 1; y <= m; y++) {
std::deque<std::pair<int, int>> q;
for (int j = 1, x = n; x; j++, x--) {
if (g[x][y]) {
q.clear();
} else {
while (!q.empty() && q.back().second < f[x][y] - j) q.pop_back();
q.push_back(std::make_pair(j, f[x][y] - j));
while (!q.empty() && j - q.front().first > len) q.pop_front();
f[x][y] = q.front().second + j;
ans = std::max(ans, f[x][y]);
}
}
}
break;
}
case 2: { // 下
for (int y = 1; y <= m; y++) {
std::deque<std::pair<int, int>> q;
for (int j = 1, x = 1; x <= n; j++, x++) {
if (g[x][y]) {
q.clear();
} else {
while (!q.empty() && q.back().second < f[x][y] - j) q.pop_back();
q.push_back(std::make_pair(j, f[x][y] - j));
while (!q.empty() && j - q.front().first > len) q.pop_front();
f[x][y] = q.front().second + j;
ans = std::max(ans, f[x][y]);
}
}
}
break;
}
case 3: { // 左
for (int x = 1; x <= n; x++) {
std::deque<std::pair<int, int>> q;
for (int j = 1, y = m; y; j++, y--) {
if (g[x][y]) {
q.clear();
} else {
while (!q.empty() && q.back().second < f[x][y] - j) q.pop_back();
q.push_back(std::make_pair(j, f[x][y] - j));
while (!q.empty() && j - q.front().first > len) q.pop_front();
f[x][y] = q.front().second + j;
ans = std::max(ans, f[x][y]);
}
}
}
break;
}
case 4: { // 右
for (int x = 1; x <= n; x++) {
std::deque<std::pair<int, int>> q;
for (int j = 1, y = 1; y <= m; j++, y++) {
if (g[x][y]) {
q.clear();
} else {
while (!q.empty() && q.back().second < f[x][y] - j) q.pop_back();
q.push_back(std::make_pair(j, f[x][y] - j));
while (!q.empty() && j - q.front().first > len) q.pop_front();
f[x][y] = q.front().second + j;
ans = std::max(ans, f[x][y]);
}
}
}
break;
}
}
}
cout << ans << endl;
return 0;
}