#include using namespace std; int n; double sum = 0.00; pair a[1005]; int main() { cin >> n; for (int i = 1; i <= n; i++) { cin >> a[i].first; a[i].second = i; } sort(a + 1, a + 1 + n); for (int i = 1; i <= n; i++) { cout << a[i].second << ' '; sum += a[i].first * (n - i); } cout << endl; cout << fixed << setprecision(2) << sum / n << endl; return 0; }