#include #include #include using std::cin; using std::cout; using std::endl; // Limits const int N = 105; int n, x, ans1, ans2; std::vector g[N]; int din[N], dout[N]; // 图的入度、出度 // Tarjan int cnt, dfn[N], low[N]; int scc_cnt, id[N]; std::stack st; bool vis[N]; void tarjan(int u) { dfn[u] = low[u] = ++cnt; st.push(u); vis[u] = true; for (int v : g[u]) { if (!dfn[v]) { tarjan(v); low[u] = std::min(low[u], low[v]); } else if (vis[v]) { low[u] = std::min(low[u], dfn[v]); } } if (dfn[u] == low[u]) { scc_cnt++; int v; do { v = st.top(); st.pop(); id[v] = scc_cnt; vis[v] = false; } while (v != u); } } int main() { cin >> n; for (int i = 1; i <= n; i++) { while (cin >> x, x) { g[i].push_back(x); } } for (int i = 1; i <= n; i++) { if (!dfn[i]) { tarjan(i); } } for (int i = 1; i <= n; i++) { for (int v : g[i]) { if (id[i] != id[v]) { dout[id[i]]++; din[id[v]]++; } } } for (int i = 1; i <= scc_cnt; i++) { if (!din[i]) ans1++; if (!dout[i]) ans2++; } cout << ans1 << endl << (scc_cnt == 1 ? 0 : std::max(ans1, ans2)) << endl; return 0; }