#include using namespace std; int n, k; long long a, cnt, sum[1000005]; int main() { cin >> n >> k; for (int i = 1; i < n; i++) { cin >> a; sum[i] = sum[i - 1] + a; } cnt = sum[k]; for (int i = 2; i <= n - k; i++) { cnt = max(cnt, sum[i + k - 1] - sum[i - 1]); } cout << sum[n - 1] - cnt << endl; return 0; }