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36. 合并两个排序的链表
https://www.acwing.com/problem/content/submission/code_detail/14064359/
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AcWing/36/36.cpp
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24
AcWing/36/36.cpp
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/**
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* Definition for singly-linked list.
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* struct ListNode {
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* int val;
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* ListNode *next;
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* ListNode(int x) : val(x), next(NULL) {}
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* };
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*/
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class Solution {
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public:
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ListNode* merge(ListNode* l1, ListNode* l2) {
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if (l1 == nullptr) {
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return l2;
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} else if (l2 == nullptr) {
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return l1;
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} else if (l1->val < l2->val) {
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l1->next = merge(l1->next, l2);
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return l1;
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} else {
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l2->next = merge(l1, l2->next);
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return l2;
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}
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}
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};
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