L - Leverage MDT

https://codeforces.com/gym/102428/submission/177267446

Gym/102428/L/L.cpp

@@ -0,0 +1,58 @@
+#include <iostream>
+#include <stack>
+#include <utility>
+
+using std::cin;
+using std::cout;
+const char endl = '\n';
+
+const int N = 1005;
+
+int n, m, f[N][N], ans;
+bool g[N][N];
+
+int main() {
+    std::ios::sync_with_stdio(false);
+    cin.tie(nullptr);
+
+    cin >> n >> m;
+
+    for (int i = 1; i <= n; i++) {
+        for (int j = 1; j <= m; j++) {
+            char c;
+
+            cin >> c;
+
+            g[i][j] = c == 'G';
+            f[i][j] = g[i][j] == g[i][j - 1] ? f[i][j - 1] + 1 : 1;
+        }
+    }
+
+    for (int p = 1; p <= m; p++) {
+        std::stack<std::pair<int, int>> st;
+
+        for (int i = 1; i <= n; i++) {
+            int l = 0;
+
+            while (!st.empty() && f[st.top().first][p] >= f[i][p]) {
+                l += st.top().second;
+                ans = std::max(ans, std::min(f[st.top().first][p], l));
+                st.pop();
+            }
+
+            st.emplace(i, l + 1);
+        }
+
+        int l = 0;
+
+        while (!st.empty()) {
+            l += st.top().second;
+            ans = std::max(ans, std::min(f[st.top().first][p], l));
+            st.pop();
+        }
+    }
+
+    cout << ans * ans << endl;
+
+    return 0;
+}