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P1002 过河卒
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problem/P1002/P1002.cpp
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34
problem/P1002/P1002.cpp
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#include <bits/stdc++.h>
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using namespace std;
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const int fx[] = {0, -2, -1, 1, 2, 2, 1, -1, -2};
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const int fy[] = {0, 1, 2, 2, 1, -1, -2, -2, -1};
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int bx, by, mx, my;
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long long f[30][30];
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bool b[30][30];
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int main() {
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cin >> bx >> by >> mx >> my;
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bx += 2;
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by += 2;
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mx += 2;
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my += 2;
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f[2][2] = 1;
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b[mx][my] = true;
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for (int i = 1; i <= 8; i++) {
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b[mx + fx[i]][my + fy[i]] = true;
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}
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for (int i = 2; i <= bx; i++) {
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for (int j = 2; j <= by; j++) {
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if (b[i][j]) {
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continue;
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}
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else {
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f[i][j] = max(f[i][j], f[i - 1][j] + f[i][j - 1]);
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}
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}
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}
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cout << f[bx][by] << endl;
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return 0;
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}
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problem/P1002/data/P1002_5.in
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problem/P1002/data/P1002_5.in
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problem/P1002/data/P1002_5.out
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problem/P1002/data/P1002_5.out
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