P1898 缘分计算

R42134215

problem/P1898/P1898.cpp

@@ -0,0 +1,34 @@
+#include <bits/stdc++.h>
+
+using namespace std;
+
+string s;
+int    st, cnt = 0, a[1000005], ans[1000005];
+
+int main() {
+    cin >> s >> st;
+    for (int i = 0; i < s.size(); i++) {
+        a[i] = s[i] - 'A' + st;
+    }
+    for (int i = s.size() - 1; i >= 0; i--) {
+        while (a[i] > 0) {
+            ans[++cnt] = a[i] % 10;
+            a[i] /= 10;
+        }
+    }
+    for (int i = cnt - 1; i >= 3; i--) {
+        for (int j = 1; j <= i; j++) {
+            ans[j] = (ans[j] + ans[j + 1]) % 10;
+        }
+    }
+    if (ans[3] == 1 && ans[2] == 0 && ans[1] == 0) {
+        cout << 100 << endl;
+    }
+    else if ((ans[2] + ans[3]) % 10) {
+        cout << (ans[2] + ans[3]) % 10 << (ans[1] + ans[2]) % 10 << endl;
+    }
+    else {
+        cout << (ans[1] + ans[2]) % 10 << endl;
+    }
+    return 0;
+}