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D - ±1 Operation 2
https://atcoder.jp/contests/abc255/submissions/32405572
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AtCoder/ABC255/D/D.cpp
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42
AtCoder/ABC255/D/D.cpp
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#include <iostream>
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#include <algorithm>
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using std::cin;
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using std::cout;
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const char endl = '\n';
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const int N = 2e5 + 5;
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int n, q, x, a[N];
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long long s[N], s2[N];
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int main() {
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std::ios::sync_with_stdio(false);
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cin.tie(nullptr);
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cin >> n >> q;
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for (int i = 1; i <= n; i++) {
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cin >> a[i];
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}
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std::sort(a + 1, a + 1 + n);
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for (int i = 1; i <= n; i++) {
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s[i] = s[i - 1] + a[i];
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}
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while (q--) {
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cin >> x;
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if (x <= a[1] || x >= a[n]) {
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cout << std::abs(s[n] - 1ll * x * n) << endl;
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} else {
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int p = std::lower_bound(a + 1, a + 1 + n, x) - a - 1;
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cout << (1ll * x * p - s[p]) + (s[n] - s[p] - 1ll * x * (n - p)) << endl;
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}
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}
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return 0;
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}
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