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OI-codes/LibreOJ/110/110.cpp

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#include <bits/stdc++.h>
using namespace std;
long long inv[20000005];
int main() {
inv[0] = 0;
inv[1] = 1;
int n, p;
scanf("%d%d", &n, &p);
printf("1\n");
for (int i = 2; i <= n; ++i) {
inv[i] = (long long)p - (p / i) * inv[p % i] % p;
printf("%d\n", inv[i]);
}
return 0;
}