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OI-codes/Luogu/P3373/P3373.cpp

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#include <bits/stdc++.h>
using namespace std;
struct node {
int l, r;
long long s, d, x;
node() {
l = r = s = d = 0;
x = 1;
}
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node(int _l, int _r) {
l = _l, r = _r;
s = d = 0;
x = 1;
}
} tr[100005 << 2];
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int n, m, p, op, x, y;
long long k, a[100005];
/**
* @brief
* @param u
*/
void pushup(int u) {
tr[u].s = (tr[u << 1].s + tr[u << 1 | 1].s) % p;
}
/**
* @brief
* @param u
* @attention
*/
void pushdown(int u) {
// 左子树
tr[u << 1].s = ((tr[u << 1].s * tr[u].x) + (tr[u << 1].r - tr[u << 1].l + 1) * tr[u].d) % p;
tr[u << 1].x = tr[u << 1].x * tr[u].x % p;
tr[u << 1].d = (tr[u << 1].d * tr[u].x + tr[u].d) % p;
// 右子树
tr[u << 1 | 1].s = ((tr[u << 1 | 1].s * tr[u].x) + (tr[u << 1 | 1].r - tr[u << 1 | 1].l + 1) * tr[u].d) % p;
tr[u << 1 | 1].x = tr[u << 1 | 1].x * tr[u].x % p;
tr[u << 1 | 1].d = (tr[u << 1 | 1].d * tr[u].x + tr[u].d) % p;
// 清除懒标记
tr[u].d = 0;
tr[u].x = 1;
}
/**
* @brief 线
* @param u
* @param l
* @param r
*/
void build(int u, int l, int r) {
tr[u] = node(l, r);
if (l == r) {
tr[u].s = a[l] % p;
return;
}
int mid = l + r >> 1;
build(u << 1, l, mid);
build(u << 1 | 1, mid + 1, r);
pushup(u);
}
/**
* @brief
* @details [l, r] d
* @param u
* @param l
* @param r
* @param x
* @param d
*/
void modify(int u, int l, int r, long long x, long long d) {
// 被包含直接修改
if (tr[u].l >= l && tr[u].r <= r) {
tr[u].s = ((tr[u].s * x) + (tr[u].r - tr[u].l + 1) * d) % p;
tr[u].x = tr[u].x * x % p;
tr[u].d = (tr[u].d * x + d) % p;
return;
}
int mid = tr[u].l + tr[u].r >> 1;
pushdown(u); // 下放懒标记
if (l <= mid) modify(u << 1, l, r, x, d); // 和左侧有交集
if (r > mid) modify(u << 1 | 1, l, r, x, d); // 和右侧有交集
pushup(u); // 上传新信息
}
/**
* @brief
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* @param u
* @param l
* @param r
* @return int
*/
long long query(int u, int l, int r) {
if (tr[u].l >= l && tr[u].r <= r) { // 被包含直接返回
return tr[u].s;
}
int mid = tr[u].l + tr[u].r >> 1;
long long s = 0;
pushdown(u); // 下放懒标记
if (l <= mid) s = query(u << 1, l, r); // 和左侧有交集
if (r > mid) s = (s + query(u << 1 | 1, l, r)) % p; // 和右侧有交集
return s;
}
signed main() {
cin >> n >> m >> p;
for (int i = 1; i <= n; i++) {
cin >> a[i];
}
build(1, 1, n);
while (m--) {
cin >> op >> x >> y;
if (op == 1) {
cin >> k;
modify(1, x, y, k, 0);
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} else if (op == 2) {
cin >> k;
modify(1, x, y, 1, k);
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} else if (op == 3) {
cout << query(1, x, y) % p << endl;
}
}
return 0;
}