From b408afeeddd241fb1451991d32e759bef5870427 Mon Sep 17 00:00:00 2001
From: Baoshuo Ren <i@baoshuo.ren>
Date: Wed, 16 Oct 2024 11:19:34 +0800
Subject: [PATCH] =?UTF-8?q?=E3=80=90=E5=AE=9E=E8=B7=B5=E8=AF=BE=E5=86=85?=
 =?UTF-8?q?=E3=80=911.=E9=A1=BA=E5=BA=8F=E7=BB=93=E6=9E=84?=
MIME-Version: 1.0
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit

---
 【实践课内】1.顺序结构/7-1 计算摄氏温度.c | 11 +++++++++++
 【实践课内】1.顺序结构/7-2 逆序的三位数.c | 18 ++++++++++++++++++
 【实践课内】1.顺序结构/7-3 日期格式化.c   | 11 +++++++++++
 【实践课内】1.顺序结构/7-4 21-爬楼梯.c    | 11 +++++++++++
 4 files changed, 51 insertions(+)
 create mode 100644 【实践课内】1.顺序结构/7-1 计算摄氏温度.c
 create mode 100644 【实践课内】1.顺序结构/7-2 逆序的三位数.c
 create mode 100644 【实践课内】1.顺序结构/7-3 日期格式化.c
 create mode 100644 【实践课内】1.顺序结构/7-4 21-爬楼梯.c

diff --git a/【实践课内】1.顺序结构/7-1 计算摄氏温度.c b/【实践课内】1.顺序结构/7-1 计算摄氏温度.c
new file mode 100644
index 0000000..a94a5c9
--- /dev/null
+++ b/【实践课内】1.顺序结构/7-1 计算摄氏温度.c	
@@ -0,0 +1,11 @@
+#include <stdio.h>
+
+int main() {
+    int f;
+
+    scanf("%d", &f);
+
+    printf("Celsius = %d\n", 5 * (f - 32) / 9);
+
+    return 0;
+}
diff --git a/【实践课内】1.顺序结构/7-2 逆序的三位数.c b/【实践课内】1.顺序结构/7-2 逆序的三位数.c
new file mode 100644
index 0000000..493c050
--- /dev/null
+++ b/【实践课内】1.顺序结构/7-2 逆序的三位数.c	
@@ -0,0 +1,18 @@
+#include <stdio.h>
+
+int x;
+
+int main() {
+    scanf("%d", &x);
+
+    int res = 0;
+
+    while (x) {
+        res = (res * 10) + (x % 10);
+        x /= 10;
+    }
+
+    printf("%d\n", res);
+    
+    return 0;
+}
diff --git a/【实践课内】1.顺序结构/7-3 日期格式化.c b/【实践课内】1.顺序结构/7-3 日期格式化.c
new file mode 100644
index 0000000..89c2fce
--- /dev/null
+++ b/【实践课内】1.顺序结构/7-3 日期格式化.c	
@@ -0,0 +1,11 @@
+#include <stdio.h>
+
+int main() {
+    int y, m, d;
+
+    scanf("%2d-%2d-%4d", &m, &d, &y);
+
+    printf("%04d-%02d-%02d\n", y, m, d);
+
+    return 0;
+}
diff --git a/【实践课内】1.顺序结构/7-4 21-爬楼梯.c b/【实践课内】1.顺序结构/7-4 21-爬楼梯.c
new file mode 100644
index 0000000..777bb23
--- /dev/null
+++ b/【实践课内】1.顺序结构/7-4 21-爬楼梯.c	
@@ -0,0 +1,11 @@
+#include <stdio.h>
+
+int a, t, b;
+
+int main() {
+    scanf("%d%d%d", &a, &t, &b);
+
+    printf("%d", 1ll * t * (b - 1) / (a - 1));
+
+    return 0;
+}