From b3f466c6edfca070d6020c2fa892f6a4218482db Mon Sep 17 00:00:00 2001
From: Baoshuo <i@baoshuo.ren>
Date: Fri, 29 Nov 2024 16:54:06 +0800
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---
 【实践课外】13.指针1/7-1 求矩阵每行元素的和.c | 37 +++++++++++++++++++
 .../7-1 求矩阵每行元素的和.md                 | 29 +++++++++++++++
 2 files changed, 66 insertions(+)
 create mode 100644 【实践课外】13.指针1/7-1 求矩阵每行元素的和.c
 create mode 100644 【实践课外】13.指针1/7-1 求矩阵每行元素的和.md

diff --git a/【实践课外】13.指针1/7-1 求矩阵每行元素的和.c b/【实践课外】13.指针1/7-1 求矩阵每行元素的和.c
new file mode 100644
index 0000000..4389dae
--- /dev/null
+++ b/【实践课外】13.指针1/7-1 求矩阵每行元素的和.c	
@@ -0,0 +1,37 @@
+#include <stdio.h>
+
+int row_sum(int *a, int n) {
+    int s = 0;
+
+    for (int i = 0; i < n; i++) {
+        s += a[i];
+    }
+
+    return s;
+}
+
+void mat_sum(int mat[][10], int n, int m, int *sum) {
+    for (int i = 0; i < n; i++) {
+        sum[i] = row_sum(mat[i], m);
+    }
+}
+
+int main() {
+    int n, m, mat[10][10], sum[10];
+
+    scanf("%d%d", &n, &m);
+
+    for (int i = 0; i < n; i++) {
+        for (int j = 0; j < m; j++) {
+            scanf("%d", &mat[i][j]);
+        }
+    }
+
+    mat_sum(mat, n, m, sum);
+
+    for (int i = 0; i < n; i++) {
+        printf("%d\n", sum[i]);
+    }
+
+    return 0;
+}
diff --git a/【实践课外】13.指针1/7-1 求矩阵每行元素的和.md b/【实践课外】13.指针1/7-1 求矩阵每行元素的和.md
new file mode 100644
index 0000000..d148108
--- /dev/null
+++ b/【实践课外】13.指针1/7-1 求矩阵每行元素的和.md	
@@ -0,0 +1,29 @@
+# 7-1 求矩阵每行元素的和
+
+本题要求编写程序，使用指针方式求一个给定的m×n矩阵各行元素之和。
+
+### 输入格式:
+
+输入第一行给出两个正整数m和n（1≤m,n≤6），再输入m行数据，每行n个整数，每个整数之间用空格分隔。
+
+### 输出格式:
+
+输出m个整数，每行1个数。
+
+### 输入样例:
+
+
+
+```in
+2 3
+1 2 3
+4 5 6
+```
+
+### 输出样例:
+
+
+```out
+6
+15
+```