【实践课内】7.数组1

【实践课内】7.数组1/7-1 fibonacci数列.c

@@ -0,0 +1,19 @@
+#include <stdio.h>
+
+int f[20] = {0, 1};
+
+int main() {
+    for (int i = 2; i < 20; i++) {
+        f[i] = f[i - 1] + f[i - 2];
+    }
+
+    for (int i = 1; i <= 12; i++) {
+        printf("%6d", f[i]);
+
+        if (i % 3 == 0) {
+            printf("\n");
+        }
+    }
+
+    return 0;
+}

【实践课内】7.数组1/7-2 输出去掉最大值和最小值后剩下数据的和.c

@@ -0,0 +1,31 @@
+#include <stdio.h>
+
+int a[10], max = -1e8, min = 1e8, sum;
+
+int main() {
+    for (int i = 1; i <= 6; i++) {
+        scanf("%d", &a[i]);
+    }
+
+    for (int i = 1; i <= 6; i++) {
+        if (a[i] > max) {
+            max = a[i];
+        }
+
+        if (a[i] < min) {
+            min = a[i];
+        }
+    }
+
+    for (int i = 1; i <= 6; i++) {
+        if (a[i] == max || a[i] == min) {
+            continue;
+        }
+
+        sum += a[i];
+    }
+
+    printf("%d\n", sum);
+
+    return 0;
+}

【实践课内】7.数组1/7-3 选择法排序.c

@@ -0,0 +1,31 @@
+#include <stdio.h>
+
+int n, a[20];
+
+int main() {
+    scanf("%d", &n);
+
+    for (int i = 1; i <= n; i++) {
+        scanf("%d", &a[i]);
+    }
+
+    for (int i = 1; i <= n; i++) {
+        for (int j = i + 1; j <= n; j++) {
+            if (a[i] < a[j]) {
+                int t = a[i];
+                a[i] = a[j];
+                a[j] = t;
+            }
+        }
+    }
+
+    for (int i = 1; i <= n; i++) {
+        if (i < n) {
+            printf("%d ", a[i]);
+        } else {
+            printf("%d\n", a[i]);
+        }
+    }
+
+    return 0;
+}

【实践课内】7.数组1/7-4 冒泡法排序.c

@@ -0,0 +1,31 @@
+#include <stdio.h>
+
+int n, k, a[200];
+
+int main() {
+    scanf("%d%d", &n, &k);
+
+    for (int i = 1; i <= n; i++) {
+        scanf("%d", &a[i]);
+    }
+
+    for (int i = 1; i <= k; i++) {
+        for (int j = 2; j <= n; j++) {
+            if (a[j] < a[j - 1]) {
+                int t = a[j];
+                a[j] = a[j - 1];
+                a[j - 1] = t;
+            }
+        }
+    }
+
+    for (int i = 1; i <= n; i++) {
+        if (i < n) {
+            printf("%d ", a[i]);
+        } else {
+            printf("%d\n", a[i]);
+        }
+    }
+
+    return 0;
+}