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47 lines
919 B
Markdown
47 lines
919 B
Markdown
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# 6-1 使用函数实现字符串部分复制
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本题要求编写函数,将输入字符串$$t$$中从第$$m$$个字符开始的全部字符复制到字符串$$s$$中。
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### 函数接口定义:
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```c++
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void strmcpy( char *t, int m, char *s );
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```
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函数`strmcpy`将输入字符串`char *t`中从第`m`个字符开始的全部字符复制到字符串`char *s`中。若`m`超过输入字符串的长度,则结果字符串应为空串。
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### 裁判测试程序样例:
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```c++
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#include <stdio.h>
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#define MAXN 20
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void strmcpy( char *t, int m, char *s );
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void ReadString( char s[] ); /* 由裁判实现,略去不表 */
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int main()
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{
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char t[MAXN], s[MAXN];
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int m;
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scanf("%d\n", &m);
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ReadString(t);
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strmcpy( t, m, s );
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printf("%s\n", s);
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return 0;
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}
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/* 你的代码将被嵌在这里 */
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```
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### 输入样例:
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```in
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7
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happy new year
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```
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### 输出样例:
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```out
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new year
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```
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